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<loc>https://lambdia.com/problems/hat-puzzle</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/problems/hat-puzzle" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/problems/hat-puzzle" />
<lastmod>2026-08-13T18:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/problems/fly-between-trains</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/problems/fly-between-trains" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/problems/fly-between-trains" />
<lastmod>2026-08-07T12:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/problems/jeep-problem</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/problems/jeep-problem" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/problems/jeep-problem" />
<lastmod>2026-08-08T06:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/problems/truel</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/problems/truel" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/problems/truel" />
<lastmod>2026-08-09T12:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/problems/mutilated-chessboard</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/problems/mutilated-chessboard" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/problems/mutilated-chessboard" />
<lastmod>2026-08-09T15:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/problems/walk-south-east-north</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/problems/walk-south-east-north" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/problems/walk-south-east-north" />
<lastmod>2026-08-09T18:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/problems/snail-on-a-pole</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/problems/snail-on-a-pole" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/problems/snail-on-a-pole" />
<lastmod>2026-08-03T08:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/problems/russian-roulette</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/problems/russian-roulette" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/problems/russian-roulette" />
<lastmod>2026-08-02T11:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/problems/false-positive-paradox</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/problems/false-positive-paradox" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/problems/false-positive-paradox" />
<lastmod>2026-07-31T00:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/problems/coin-weighing</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/problems/coin-weighing" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/problems/coin-weighing" />
<lastmod>2026-08-01T01:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/problems/boy-girl</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/problems/boy-girl" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/problems/boy-girl" />
<lastmod>2026-08-05T06:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/broken-stick-triangle</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/broken-stick-triangle" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/broken-stick-triangle" />
<video:video>
<video:title>Snap a stick twice. Do the pieces close into a triangle?</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/ILkN950o-tY/hqdefault.jpg</video:thumbnail_loc>
<video:description>Two random breaks, three pieces, and three inequalities that collapse into one. The quarter falls out of a square with no integral at all, and the average longest piece, 11/18, explains why the answer feels too low but isn't.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/ILkN950o-tY</video:player_loc>
<video:duration>747</video:duration>
<video:publication_date>2026-08-09</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-09T00:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/twenty-three-people-share-a-birthday</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/twenty-three-people-share-a-birthday" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/twenty-three-people-share-a-birthday" />
<lastmod>2026-08-08T06:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/hundred-prisoners-survive-31-percent</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/hundred-prisoners-survive-31-percent" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/hundred-prisoners-survive-31-percent" />
<lastmod>2026-08-07T06:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/switching-doors-wins-two-thirds</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/switching-doors-wins-two-thirds" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/switching-doors-wins-two-thirds" />
<lastmod>2026-08-06T06:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/eight-lilies-save-only-three-days</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/eight-lilies-save-only-three-days" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/eight-lilies-save-only-three-days" />
<video:video>
<video:title>Eight Water Lilies Buy Three Days, and Dividing Says Twenty-Six</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/a8Q-qpkUrvA/hqdefault.jpg</video:thumbnail_loc>
<video:description>One lily doubling daily covers the pond on day thirty, so eight lilies must finish in 30/8 = 3.75 days. They finish on day twenty-seven, because eight is two cubed and that slides the whole schedule exactly three days earlier. The article carries the general rule that k lilies save the floor of log base two of k, the case where five lilies save only two, and the non-overlap assumption the answer quietly rests on.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/a8Q-qpkUrvA</video:player_loc>
<video:duration>527</video:duration>
<video:publication_date>2026-08-03T14:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-03T14:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/four-gallons-from-five-and-three</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/four-gallons-from-five-and-three" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/four-gallons-from-five-and-three" />
<video:video>
<video:title>Four Gallons From a Five and a Three, and Why Coprimality Is the Trick</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/0-xvc2pnods/hqdefault.jpg</video:thumbnail_loc>
<video:description>Adding fives and threes never reaches four, and that observation is correct. It is also about the wrong set, because a pour is a subtraction and the reachable amounts are the integer combinations rather than the natural ones. An exhaustive state-graph search proves six pours is minimal, and the four missing sums turn out to be the gaps of a numerical semigroup.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/0-xvc2pnods</video:player_loc>
<video:duration>47</video:duration>
<video:publication_date>2026-08-10T06:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-10T06:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/one-weighing-finds-the-light-bag</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/one-weighing-finds-the-light-bag" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/one-weighing-finds-the-light-bag" />
<video:video>
<video:title>Ten Bags, One Reading: 55 Coins Turn the Dial Into a Label</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/Aumr9_f8oKA/hqdefault.jpg</video:thumbnail_loc>
<video:description>Taking one coin from each bag reads 9.9 ounces whichever bag is light, and the failure is blindness rather than imprecision. Loading i coins from bag i makes the dial an injective function of the culprit, at a cost of the tenth triangular number. A 45-coin variant is cheaper, and powers of two identify any subset of light bags from one reading.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/Aumr9_f8oKA</video:player_loc>
<video:duration>53</video:duration>
<video:publication_date>2026-08-10T09:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-10T09:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/light-both-ends-for-thirty-seconds</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/light-both-ends-for-thirty-seconds" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/light-both-ends-for-thirty-seconds" />
<video:video>
<video:title>Thirty Seconds From a Cord That Burns Unevenly, on Any Cord At All</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/nxC4-vmqnng/hqdefault.jpg</video:thumbnail_loc>
<video:description>Halving the length and timing the flame is not a biased estimator of half the time, it is unrelated to it: across four thousand random cords the midpoint method scattered from under fifteen seconds to over forty-five. Lighting both ends gives exactly thirty on every cord, by an argument that never evaluates the burn rate.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/nxC4-vmqnng</video:player_loc>
<video:duration>48</video:duration>
<video:publication_date>2026-08-10T12:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-10T12:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/gold-bar-in-one-two-four</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/gold-bar-in-one-two-four" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/gold-bar-in-one-two-four" />
<video:video>
<video:title>One Gold Bar, Two Cuts, Seven Evenings: 1, 2 and 4</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/iOYnGubdKpU/hqdefault.jpg</video:thumbnail_loc>
<video:description>Seven pieces cost six cuts and the schedule pays correctly, so the six-cut answer breaks one constraint and nothing else. Because the worker can hand pieces back, the contract is on his holding rather than on the transfer, and the ledger turns out to be a three-bit counter. Brute force finds 1-2-4 is the only three-piece solution.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/iOYnGubdKpU</video:player_loc>
<video:duration>51</video:duration>
<video:publication_date>2026-08-10T15:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-10T15:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/hanoi-64-rings-584-billion-years</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/hanoi-64-rings-584-billion-years" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/hanoi-64-rings-584-billion-years" />
<video:video>
<video:title>64 Rings, and 584 Billion Years at One Move a Second</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/6hL8NIW-xms/hqdefault.jpg</video:thumbnail_loc>
<video:description>Thirty-two rings really do take 136 years at a move a second, which is what makes doubling it to 272 so tempting. The exact ratio between the two cases factors as two to the thirty-two plus one, so the guess is short by more than four billion times. The article carries the lower bound the recursion alone does not give, and the 2-adic rule for which ring moves when.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/6hL8NIW-xms</video:player_loc>
<video:duration>45</video:duration>
<video:publication_date>2026-08-10T18:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-10T18:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/stock-drops-so-you-buy-it-back</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/stock-drops-so-you-buy-it-back" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/stock-drops-so-you-buy-it-back" />
<video:video>
<video:title>The Share Falls Ten Dollars and the Hedge Says Buy</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/LZ3JRi9kXRI/hqdefault.jpg</video:thumbnail_loc>
<video:description>The hedge on a long call is the slope of its value, and a convex curve flattens as you slide left, so a falling share forces a smaller short and a smaller short is a purchase. No volatility, maturity or distribution enters that argument. The rebalance buys twenty shares, and the position gains 0.9824 per share on the fall.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/LZ3JRi9kXRI</video:player_loc>
<video:duration>49</video:duration>
<video:publication_date>2026-08-11T06:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-11T06:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/two-bells-ring-together-after-60-seconds</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/two-bells-ring-together-after-60-seconds" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/two-bells-ring-together-after-60-seconds" />
<video:video>
<video:title>Two Bells, 12 and 15 Seconds Apart, Meet at a Full Minute</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/o5-dz5w1YY0/hqdefault.jpg</video:thumbnail_loc>
<video:description>Multiplying four rings a minute by five gives a quantity in inverse minutes squared, so a dimension check kills the twenty-second answer before any number theory. Converting to gaps makes the ring times two arithmetic progressions whose intersection is the least common multiple. Shift one bell by a second and the two never coincide at all.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/o5-dz5w1YY0</video:player_loc>
<video:duration>48</video:duration>
<video:publication_date>2026-08-11T09:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-11T09:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/bug-unfolds-the-room-root-5</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/bug-unfolds-the-room-root-5" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/bug-unfolds-the-room-root-5" />
<video:video>
<video:title>A Bug Walks Root Five Across a Cubic Room</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/A-fVSHIKH8o/hqdefault.jpg</video:thumbnail_loc>
<video:description>Unfolding two faces into a 2 by 1 rectangle turns the walk into a straight segment of length root five, crossing the shared edge at half height. The reflex answer of one plus root two is the same one-parameter family evaluated at the end of that edge instead of its middle, so the trap and the answer are two points on one curve.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/A-fVSHIKH8o</video:player_loc>
<video:duration>51</video:duration>
<video:publication_date>2026-08-11T12:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-11T12:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/water-and-wine-end-up-equal</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/water-and-wine-end-up-equal" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/water-and-wine-end-up-equal" />
<video:video>
<video:title>Two Jars End Up Equally Contaminated, and Conservation Proves It</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/y1lfVPg0wiA/hqdefault.jpg</video:thumbnail_loc>
<video:description>The pour back really was diluted, and the conclusion still does not follow: both jars finish at six cups, so whatever left one jar was replaced cup for cup by what arrived. That argument needs no fractions and survives terrible stirring, while the number 1.5 cups does not.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/y1lfVPg0wiA</video:player_loc>
<video:duration>49</video:duration>
<video:publication_date>2026-08-11T15:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-11T15:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/a-hundred-heads-means-a-loaded-coin</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/a-hundred-heads-means-a-loaded-coin" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/a-hundred-heads-means-a-loaded-coin" />
<video:video>
<video:title>A Hundred Heads in a Row: the Answer Is Not One Half</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/LsNFajEjfWU/hqdefault.jpg</video:thumbnail_loc>
<video:description>Coins have no memory, which is true, and nobody said this coin is fair, which is the whole problem. A fair coin explains the run with probability two to the minus one hundred while a two-headed coin explains it every time. The article locates the threshold exactly and reconciles the answer with the companion piece on ten heads, which asks a different question about a different setup.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/LsNFajEjfWU</video:player_loc>
<video:duration>46</video:duration>
<video:publication_date>2026-08-11T18:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-11T18:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/reroll-the-ones-and-expect-four</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/reroll-the-ones-and-expect-four" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/reroll-the-ones-and-expect-four" />
<video:video>
<video:title>Reroll the Ones and the Die Is Worth Four</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/WBlntLmBR04/hqdefault.jpg</video:thumbnail_loc>
<video:description>Three and a half is the exact average of a plain die, which is why it survives being double-checked. The rule does not reweight six outcomes, it deletes one, leaving a uniform payoff on five faces and an answer of four. The procedure costs 1.2 rolls on average, and the version where the reroll is your choice is a different game worth 4.25.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/WBlntLmBR04</video:player_loc>
<video:duration>50</video:duration>
<video:publication_date>2026-08-12T06:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-12T06:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/two-kings-in-a-row-is-one-in-221</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/two-kings-in-a-row-is-one-in-221" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/two-kings-in-a-row-is-one-in-221" />
<video:video>
<video:title>Two Kings Off the Top: One in 221</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/CGVPyk7QyDA/hqdefault.jpg</video:thumbnail_loc>
<video:description>Four over fifty-two squared is exactly right for the question where the first card goes back, which is what makes it hard to catch. Removing a king shrinks the numerator proportionally more than the denominator, and the counting route through 1326 two-card hands confirms one in 221 without mentioning order at all.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/CGVPyk7QyDA</video:player_loc>
<video:duration>49</video:duration>
<video:publication_date>2026-08-12T09:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-12T09:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/clock-face-split-into-three-26s</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/clock-face-split-into-three-26s" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/clock-face-split-into-three-26s" />
<video:video>
<video:title>A Clock Face in Three Pieces of 26, and No Pie Cut Ever Works</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/-xOjV0ls5lA/hqdefault.jpg</video:thumbnail_loc>
<video:description>The dial totals 78, so each piece needs 26, and the pie instinct fails on all 220 possible cuts. The proof is three lines of triangular numbers: only one pair of running totals differs by 26, which forces the first two cracks and then demands a total of 62 that does not exist.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/-xOjV0ls5lA</video:player_loc>
<video:duration>55</video:duration>
<video:publication_date>2026-08-12T12:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-12T12:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/252-staircase-paths-to-five-five</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/252-staircase-paths-to-five-five" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/252-staircase-paths-to-five-five" />
<video:video>
<video:title>252 Staircase Paths, and the Word That Replaces the Grid</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/43yAif_FHqU/hqdefault.jpg</video:thumbnail_loc>
<video:description>Every route across a five by five grid is ten steps long with exactly five going east, so counting routes is choosing which five of the ten slots are east. The reflex 1024 is the exact number of free ten-step walks, and only 252 of them arrive. Forbid the route to rise above the diagonal and the count collapses to the Catalan number 42.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/43yAif_FHqU</video:player_loc>
<video:duration>56</video:duration>
<video:publication_date>2026-08-12T15:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-12T15:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/2519-leaves-every-remainder</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/2519-leaves-every-remainder" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/2519-leaves-every-remainder" />
<video:video>
<video:title>2519, and the Shift That Turns Nine Congruences Into One</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/Imed_2jogGc/hqdefault.jpg</video:thumbnail_loc>
<video:description>Every one of the nine conditions leaves a remainder one short of its divisor, so x plus one is divisible by all of 2 through 10 and the answer is 2519. Minimality comes free, and the whole solution set is 2520k minus 1. The article carries the coprimality caveat, the near miss 209 that satisfies six of the nine, and a variant where no shift exists.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/Imed_2jogGc</video:player_loc>
<video:duration>51</video:duration>
<video:publication_date>2026-08-12T18:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-12T18:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/pebble-needs-3-6-flips-not-4</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/pebble-needs-3-6-flips-not-4" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/pebble-needs-3-6-flips-not-4" />
<video:video>
<video:title>3.6 Flips, Not 4, and the Beautiful Argument That Says Otherwise</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/IBnMVPKa6eQ/hqdefault.jpg</video:thumbnail_loc>
<video:description>A pebble climbing four boxes on coin flips needs 18/5 flips on average, and the two-line renewal argument that gives 4 is wrong. Its premise is true, since half of all games really do end on flip two, but the non-finishing half is two different states: tails-tails sends the pebble home while heads-heads leaves it on box 3, one flip from the exit and worth only 14/5.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/IBnMVPKa6eQ</video:player_loc>
<video:duration>58</video:duration>
<video:publication_date>2026-08-13T06:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-13T06:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/two-thirds-of-a-dollar-before-the-six</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/two-thirds-of-a-dollar-before-the-six" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/two-thirds-of-a-dollar-before-the-six" />
<video:video>
<video:title>Two Thirds of a Dollar, and the Branch That Pays Nothing</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/6eWUW3KunmA/hqdefault.jpg</video:thumbnail_loc>
<video:description>The pile really does average exactly one dollar, which is why almost everyone answers one dollar and why the trap is a correct calculation of the wrong quantity. The play is worth two thirds, because the roll that ends the game pays on two of its three faces and that roll is independent of how big the pile grew.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/6eWUW3KunmA</video:player_loc>
<video:duration>51</video:duration>
<video:publication_date>2026-08-13T09:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-13T09:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/say-six-and-win-the-race-to-fifty</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/say-six-and-win-the-race-to-fifty" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/say-six-and-win-the-race-to-fifty" />
<video:video>
<video:title>Say Six: The Only Opening That Wins the Race to Fifty</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/6pogQzUIRk8/hqdefault.jpg</video:thumbnail_loc>
<video:description>Counting to fifty in steps of one to ten, the first player wins, and exactly one of the ten legal openings does it. The stations are 6, 17, 28, 39 and 50, spaced eleven apart because eleven is one more than the largest legal step. The article carries the residue argument that proves the opening is unique, and the target 55 where the advantage flips.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/6pogQzUIRk8</video:player_loc>
<video:duration>54</video:duration>
<video:publication_date>2026-08-13T12:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-13T12:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/three-switches-one-visit-use-heat</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/three-switches-one-visit-use-heat" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/three-switches-one-visit-use-heat" />
<video:video>
<video:title>Three Switches, One Visit, and the State Light Cannot Carry</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/o9Ew4p43rh0/hqdefault.jpg</video:thumbnail_loc>
<video:description>Six pairings have to be separated by a single observation, and a light-only strategy always leaves at least two candidates standing. Warmth is a genuine third readable state, and three states handed to three bulbs give exactly six readings, one per pairing. The article carries the impossibility count and the four-switch case where the trick fails.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/o9Ew4p43rh0</video:player_loc>
<video:duration>55</video:duration>
<video:publication_date>2026-08-13T15:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-13T15:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/blind-man-deduces-his-hat-is-blue</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/blind-man-deduces-his-hat-is-blue" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/blind-man-deduces-his-hat-is-blue" />
<video:video>
<video:title>Blue, and the Two Sentences That Contain No Answer</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/uneqvdC4oEA/hqdefault.jpg</video:thumbnail_loc>
<video:description>Of the eight colour triples, seven are feasible from a pool of three blue hats and two red. The first silence removes one, the second removes two more, and all four survivors put a blue hat on the third man, which is what makes his answer a deduction rather than a lucky call. A pool sweep shows three blue and two red is the only small pool where the story can happen.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/uneqvdC4oEA</video:player_loc>
<video:duration>55</video:duration>
<video:publication_date>2026-08-13T18:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-13T18:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/stopping-at-the-first-boy-keeps-fifty-fifty</loc>
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<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/stopping-at-the-first-boy-keeps-fifty-fifty" />
<video:video>
<video:title>One Boy Per Family, One Girl Per Family, and Why ln 2 Is Not a Half</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/m7lORjleAnQ/hqdefault.jpg</video:thumbnail_loc>
<video:description>Every family averages exactly one girl and contains exactly one boy, so the ratio of expected counts is exactly one half and a large town splits evenly. The expected share inside a single family is not one half but ln 2, and it is still 0.5249 across ten families, with the excess falling off like one over four m.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/m7lORjleAnQ</video:player_loc>
<video:duration>47</video:duration>
<video:publication_date>2026-08-14T06:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-14T06:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/the-fly-flies-twenty-miles</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/the-fly-flies-twenty-miles" />
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<video:video>
<video:title>Twenty Miles of Fly, and the Series Nobody Should Finish</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/-qDGL7R7Hts/hqdefault.jpg</video:thumbnail_loc>
<video:description>Two riders twenty-five miles apart close at fifty miles an hour, so a forty mile an hour fly shuttling between them flies exactly twenty miles. The series of shuttle legs gives the same twenty, with a first leg of 100/7 and a round-trip ratio of 1/21, but no finite number of legs ever reaches it: after eighty legs the exact total is twenty minus about 2.6e-52. The general law is wD/(a+b), and it holds identically in the rider speeds rather than by luck at 20 and 30.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/-qDGL7R7Hts</video:player_loc>
<video:duration>44</video:duration>
<video:publication_date>2026-08-07T12:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-07T12:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/five-coins-against-four-is-a-coin-flip</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/five-coins-against-four-is-a-coin-flip" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/five-coins-against-four-is-a-coin-flip" />
<video:video>
<video:title>Five Coins Against Four Is Exactly a Coin Flip</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/IuglTT2w82U/hqdefault.jpg</video:thumbnail_loc>
<video:description>You toss five fair coins, I toss four, and you win on strictly more heads: the answer is exactly 256 of the 512 outcomes. Because you hold one coin more, "not strictly more heads" and "strictly more tails" are the same event, and turning every coin over is a bijection between them. The fifth coin is worth nearly fourteen percentage points over the 93/256 you would have without it, and none of that is an edge.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/IuglTT2w82U</video:player_loc>
<video:duration>44</video:duration>
<video:publication_date>2026-08-07T15:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-07T15:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/only-perfect-squares-stay-lit</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/only-perfect-squares-stay-lit" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/only-perfect-squares-stay-lit" />
<video:video>
<video:title>A Hundred Bulbs, 482 Flips, and Ten Survivors</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/_vfuQxkS2-o/hqdefault.jpg</video:thumbnail_loc>
<video:description>Person k flips every bulb that is a multiple of k, and after a hundred passes exactly the ten perfect squares are lit. Bulb n is flipped once per divisor, and the pairing d against n/d is fixed-point free unless n is a square, so the parity is decided by algebra rather than by accumulation. The lit fraction is one over the square root of the row, and stopping the process at person 50 inverts the answer to 54 bulbs.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/_vfuQxkS2-o</video:player_loc>
<video:duration>45</video:duration>
<video:publication_date>2026-08-07T18:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-07T18:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/833-apples-across-a-thousand-miles</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/833-apples-across-a-thousand-miles" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/833-apples-across-a-thousand-miles" />
<video:video>
<video:title>833 Apples, and the Surplus Apple That Rides for Free</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/fCbwJrJPzyY/hqdefault.jpg</video:thumbnail_loc>
<video:description>A driver who eats one apple per loaded mile delivers 833 of 3000 across a thousand miles, because the price of a mile is the ceiling of the stock over the truck's capacity: three apples, then two, then one. The continuous optimum is 2500/3, but rounding the switch point down to mile 333 leaves 2001 apples needing three passes and produces a fake 834. A lower bound on loaded traversals proves 833 optimal without a dynamic programme, and the free return legs are the clause that separates 833 from 533.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/fCbwJrJPzyY</video:player_loc>
<video:duration>50</video:duration>
<video:publication_date>2026-08-08T06:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-08T06:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/hands-at-three-fifteen-are-7-point-5-degrees</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/hands-at-three-fifteen-are-7-point-5-degrees" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/hands-at-three-fifteen-are-7-point-5-degrees" />
<video:video>
<video:title>Seven and a Half Degrees at a Quarter Past Three</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/VfEObVfpPfs/hqdefault.jpg</video:thumbnail_loc>
<video:description>At 3:15 the minute hand is on the 3 and the angle between the hands looks like zero. It is 7.5 degrees, or pi/24 radians, because the hour hand crawls a quarter of the way from the 3 to the 4 while the minute hand travels a full lap. The zero answer is exact for a clock whose hour hand waits on each numeral and jumps, which is not a clock that exists.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/VfEObVfpPfs</video:player_loc>
<video:duration>42</video:duration>
<video:publication_date>2026-08-08T09:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-08T09:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/product-of-two-uniforms-beats-half-15-percent</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/product-of-two-uniforms-beats-half-15-percent" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/product-of-two-uniforms-beats-half-15-percent" />
<video:video>
<video:title>Two Random Numbers, One Hyperbola, and 15.3 Percent</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/iebJ3pwYYC4/hqdefault.jpg</video:thumbnail_loc>
<video:description>Draw X and Y uniformly from the unit interval and their product beats a half with probability (1 - ln 2)/2, about 15.3 percent. The reflex answer of a quarter counts a condition that is genuinely necessary and treats it as sufficient, which is why 0.8 times 0.6 sits inside the quarter square and still loses. The hyperbola y = 1/(2x) cuts the winners down to a sliver, and one integral measures it.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/iebJ3pwYYC4</video:player_loc>
<video:duration>42</video:duration>
<video:publication_date>2026-08-08T12:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-08T12:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/checkerboard-stacks-fill-a-cube</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/checkerboard-stacks-fill-a-cube" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/checkerboard-stacks-fill-a-cube" />
<video:video>
<video:title>A Board of Stacks That Folds Into a Cube</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/aUhAi4RjaV4/hqdefault.jpg</video:thumbnail_loc>
<video:description>Stack i + j - 1 cubes on every square of a 20 by 20 board and the total is 8000, which is 20 cubed. Folding the board across the squares that are exactly 20 deep pairs every stack with a mirror stack, and each pair adds to 40, so the average depth is 20. The double sum gets the same answer and is merely slow, and the main diagonal is the fold that proves nothing.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/aUhAi4RjaV4</video:player_loc>
<video:duration>51</video:duration>
<video:publication_date>2026-08-08T15:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-08T15:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/rock-overboard-lowers-the-water</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/rock-overboard-lowers-the-water" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/rock-overboard-lowers-the-water" />
<video:video>
<video:title>Why Throwing a Rock Overboard Lowers the Pool</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/cSfLhq-jWCU/hqdefault.jpg</video:thumbnail_loc>
<video:description>A boat carrying a dense rock floats in a pool; the rock goes over the side and sinks. The mass inside the pool is unchanged, so the reflex says the level cannot move, but it falls by exactly (d-1)V/A. The article carries the algebra the fifty-second version had no room for, plus the force balance on the sunk rock that shows the floor is where the argument closes.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/cSfLhq-jWCU</video:player_loc>
<video:duration>45</video:duration>
<video:publication_date>2026-08-08T18:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-08-08T18:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/real-probabilities-do-not-price-the-call</loc>
<xhtml:link rel="alternate" hreflang="en" href="https://lambdia.com/a/real-probabilities-do-not-price-the-call" />
<xhtml:link rel="alternate" hreflang="x-default" href="https://lambdia.com/a/real-probabilities-do-not-price-the-call" />
<video:video>
<video:title>An 80% Chance of $20 Does Not Make the Option Worth $16</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/5cU4I-_RyEA/hqdefault.jpg</video:thumbnail_loc>
<video:description>A stock at 100 goes to 130 with probability 0.8 or 70 with probability 0.2, rates are zero, and the right to buy at 110 is worth 10 rather than 16. A third of a share funded by borrowing 70/3 reproduces both payoffs and costs 10 today, which prices the option without using a probability anywhere. The general risk-neutral probability (S-d)/(u-d) is a half here only because rates are zero and 100 sits midway between the two outcomes.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/5cU4I-_RyEA</video:player_loc>
<video:duration>55</video:duration>
<video:publication_date>2026-08-09T06:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
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<lastmod>2026-08-09T06:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/seven-sixteenths-chance-of-meeting</loc>
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<video:video>
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<video:thumbnail_loc>https://i.ytimg.com/vi/OViBuQgCLv8/hqdefault.jpg</video:thumbnail_loc>
<video:description>Two people arrive at random inside the same hour and each waits fifteen minutes, so the reflex answer is a quarter. Drawing both arrival times as one point in a 60 by 60 square turns the question into an area, and the two corner triangles it leaves out have legs of 45, giving 7/16 rather than 1/4. The general formula n(2T-n)/T squared shows why the first minutes of patience buy the most.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/OViBuQgCLv8</video:player_loc>
<video:duration>47</video:duration>
<video:publication_date>2026-08-09T09:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
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</video:video>
<lastmod>2026-08-09T09:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/weakest-player-should-waste-the-turn</loc>
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<video:video>
<video:title>The Weakest Player Should Waste the Turn</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/NIvPJupmu1I/hqdefault.jpg</video:thumbnail_loc>
<video:description>You hit one time in ten, your two opponents three and six, and you shoot first. Firing into the air is worth 965/4736 = 20.376%, which beats removing the strongest player by 0.195 percentage points, because a landed hit drops you into the duel you must enter second at 7/37 rather than first at 10/37. The article carries all three option values, the fixed points they solve, and the single Nash equilibrium that turns the usual assumption into a conclusion.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/NIvPJupmu1I</video:player_loc>
<video:duration>48</video:duration>
<video:publication_date>2026-08-09T12:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
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</video:video>
<lastmod>2026-08-09T12:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/mutilated-chessboard-resists-dominoes</loc>
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<video:video>
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<video:thumbnail_loc>https://i.ytimg.com/vi/kxLgrEIrwVg/hqdefault.jpg</video:thumbnail_loc>
<video:description>Cut two diagonally opposite corners off a chessboard and 62 = 2 x 31 stays true, yet nothing fits. Writing the colour of a square as the sign (-1)^(i+j) turns the argument into arithmetic: every domino sums to zero, the two lost corners both carried +1, and the board left over is 30 against 32. The converse, Gomory's theorem, is the harder half and it goes the other way.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/kxLgrEIrwVg</video:player_loc>
<video:duration>43</video:duration>
<video:publication_date>2026-08-09T15:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
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<lastmod>2026-08-09T15:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/infinitely-many-south-east-north-loops</loc>
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<video:video>
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<video:thumbnail_loc>https://i.ytimg.com/vi/sp91kvzB8Q0/hqdefault.jpg</video:thumbnail_loc>
<video:description>The North Pole really is a solution, so the trap is only the words "and nowhere else". A mile north of the parallel whose whole lap measures 1/n of a mile, the eastward mile is n exact revolutions, which puts a starting circle 1.159 miles from the South Pole for one lap, 1.080 for two, 1.053 for three. Every point of every circle works, so the honest count is uncountable rather than infinite.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/sp91kvzB8Q0</video:player_loc>
<video:duration>50</video:duration>
<video:publication_date>2026-08-09T18:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
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</video:video>
<lastmod>2026-08-09T18:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/ten-heads-in-a-row-is-a-coin-flip</loc>
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<video:video>
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<video:thumbnail_loc>https://i.ytimg.com/vi/aAHpjbtS3Pg/hqdefault.jpg</video:thumbnail_loc>
<video:description>Draw one coin from a thousand, flip ten heads, and the chance it is the two-headed one is 0.5062. Both reflex answers miss, in opposite directions: ninety-nine percent ignores the bag, one in a thousand ignores the flips. Counting patterns gets the exact figure with no Bayes notation at all, and the reason it lands on a coin flip is that 2^10 happens to sit next to the size of the bag.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/aAHpjbtS3Pg</video:player_loc>
<video:duration>613</video:duration>
<video:publication_date>2026-08-03T11:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
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</video:video>
<lastmod>2026-08-03T11:00:00.000Z</lastmod>
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<video:thumbnail_loc>https://i.ytimg.com/vi/qJMMBsGDFu4/hqdefault.jpg</video:thumbnail_loc>
<video:description>Three feet up each day, one foot back each night, ten feet to climb. Dividing ten by the net two feet a day gives five days, and it charges the snail for a night it never spends. The dawn heights settle the day, the last climb settles the moment, and the closed form the video had no room to voice is a single ceiling function.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/qJMMBsGDFu4</video:player_loc>
<video:duration>565</video:duration>
<video:publication_date>2026-08-03T08:00:00Z</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
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<lastmod>2026-08-03T08:00:00.000Z</lastmod>
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<loc>https://lambdia.com/a/one-lone-white-marble-gives-75-percent</loc>
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<video:description>Fifty white marbles, fifty black, two jars, and a fair coin choosing which jar gets drawn from. The even split gives exactly one half, and so does every other split where the jars are the same size. Isolating a single white marble reaches 74/99, an exchange argument proves nothing beats it, and three quarters turns out to be a ceiling no arrangement ever touches.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/Czy36QsGzgw</video:player_loc>
<video:duration>699</video:duration>
<video:publication_date>2026-08-02T17:00:00Z</video:publication_date>
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<lastmod>2026-08-02T17:00:00.000Z</lastmod>
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<url>
<loc>https://lambdia.com/a/683-chips-for-100-cookies</loc>
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<video:thumbnail_loc>https://i.ytimg.com/vi/LWIArp86p0U/hqdefault.jpg</video:thumbnail_loc>
<video:description>Drop chips at random into dough, cut it into a hundred cookies, and ask how many chips guarantee no bare cookie nine times out of ten. Five hundred chips, five per cookie on average, works about half the time. Inclusion-exclusion pins the answer at 683, a closed form you can solve on a whiteboard agrees, and the coupon collector's mean of 518.7 is the sophisticated wrong answer.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/LWIArp86p0U</video:player_loc>
<video:duration>616</video:duration>
<video:publication_date>2026-08-02T14:00:00Z</video:publication_date>
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<lastmod>2026-08-02T14:00:00.000Z</lastmod>
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<url>
<loc>https://lambdia.com/a/never-respin-the-cylinder</loc>
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<video:thumbnail_loc>https://i.ytimg.com/vi/UfsKaww9BQQ/hqdefault.jpg</video:thumbnail_loc>
<video:description>Six slots in a ring, two of them marked side by side. You land on a blank one and get one move: step forward, or draw a fresh slot at random. Both look like two in six. Stepping is one in four, drawing again is one in three, and the whole gap comes from the fact that the two marks are touching. Pull them apart and the advice reverses.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/UfsKaww9BQQ</video:player_loc>
<video:duration>556</video:duration>
<video:publication_date>2026-08-02T11:00:00Z</video:publication_date>
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<lastmod>2026-08-02T11:00:00.000Z</lastmod>
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<loc>https://lambdia.com/a/cube-outer-layer-488</loc>
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<video:title>Almost everyone gets this cube question wrong</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/RwUtDxfaadE/hqdefault.jpg</video:thumbnail_loc>
<video:description>Strip the outer shell off a ten-by-ten-by-ten block of unit cubes and count what falls. The reflex answer, 271, is arithmetic done correctly on the wrong picture: a shell leaves from both opposing faces, so every axis loses two units and not one. Two independent counts land on 488, and the general shell turns out to grow like a surface rather than a volume.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/RwUtDxfaadE</video:player_loc>
<video:duration>591</video:duration>
<video:publication_date>2026-08-02T08:00:00Z</video:publication_date>
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<lastmod>2026-08-02T08:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/bayes-theorem-false-positive-paradox</loc>
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<video:title>Your positive test result. Almost everyone reads it wrong.</video:title>
<video:thumbnail_loc>https://i.ytimg.com/vi/32JruhITzzE/hqdefault.jpg</video:thumbnail_loc>
<video:description>A disease one person in two hundred carries, and a test with no false negatives at all. The reflex answer to a positive result is above ninety percent, and it is wrong by more than a factor of ten. A crowd of a thousand people shows why before the algebra does, and Bayes puts the exact figure at 100/1493.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/32JruhITzzE</video:player_loc>
<video:duration>240</video:duration>
<video:publication_date>2026-07-31</video:publication_date>
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<lastmod>2026-07-31T00:00:00.000Z</lastmod>
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<loc>https://lambdia.com/a/zero-volatility-option</loc>
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<video:video>
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<video:thumbnail_loc>https://i.ytimg.com/vi/NAgz65xbYx4/hqdefault.jpg</video:thumbnail_loc>
<video:description>A stock with zero volatility, a call struck at the money, and the reflex answer — zero — that fails real trading interviews. One arbitrage argument prices it three different ways, and Black–Scholes agrees on the way out.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/NAgz65xbYx4</video:player_loc>
<video:duration>410</video:duration>
<video:publication_date>2026-07-22</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
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<lastmod>2026-07-22T00:00:00.000Z</lastmod>
</url>
<url>
<loc>https://lambdia.com/a/x-plus-one-over-x-power-sums</loc>
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<lastmod>2026-07-21T00:00:00.000Z</lastmod>
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<url>
<loc>https://lambdia.com/fr/a/x-plus-one-over-x-power-sums</loc>
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<lastmod>2026-07-21T00:00:00.000Z</lastmod>
</url>
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<loc>https://lambdia.com/a/random-triangle-circle-center</loc>
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<video:video>
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<video:thumbnail_loc>https://i.ytimg.com/vi/SJnMzsgC0X4/hqdefault.jpg</video:thumbnail_loc>
<video:description>Drop three random points on a circle and the triangle contains the center exactly a quarter of the time. Two proofs: an honest average, then two coins wearing a geometry costume.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/SJnMzsgC0X4</video:player_loc>
<video:duration>937</video:duration>
<video:publication_date>2026-07-19</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
</video:video>
<lastmod>2026-07-19T00:00:00.000Z</lastmod>
</url>
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<video:thumbnail_loc>https://i.ytimg.com/vi/IM-MO_QX8tk/hqdefault.jpg</video:thumbnail_loc>
<video:description>Infinitely many lines separate the same data; only the widest street generalizes. And once it's found, almost none of your points were holding it up.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/IM-MO_QX8tk</video:player_loc>
<video:duration>704</video:duration>
<video:publication_date>2026-07-19</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
<video:uploader info="https://lambdia.com">Lambdia</video:uploader>
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<loc>https://lambdia.com/a/every-tournament-has-a-hamiltonian-path</loc>
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<video:thumbnail_loc>https://i.ytimg.com/vi/ltwBIjps338/hqdefault.jpg</video:thumbnail_loc>
<video:description>Round-robin results can be pure chaos, cycles everywhere, no champion. A one-move induction still lines everyone up so each player beat the next.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/ltwBIjps338</video:player_loc>
<video:duration>591</video:duration>
<video:publication_date>2026-07-19</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
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<loc>https://lambdia.com/a/polynomials-that-map-q-onto-q</loc>
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<video:thumbnail_loc>https://i.ytimg.com/vi/XAQdYts7hlk/hqdefault.jpg</video:thumbnail_loc>
<video:description>A line with rational coefficients maps ℚ onto ℚ. Nothing curved ever does. Three filters — interpolation, shape, denominators — leave the full classification.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/XAQdYts7hlk</video:player_loc>
<video:duration>1096</video:duration>
<video:publication_date>2026-07-19</video:publication_date>
<video:family_friendly>yes</video:family_friendly>
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<lastmod>2026-07-19T00:00:00.000Z</lastmod>
</url>
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<loc>https://lambdia.com/a/ninety-coins-need-five-weighings</loc>
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<video:thumbnail_loc>https://i.ytimg.com/vi/s2Gwg6nLdlY/hqdefault.jpg</video:thumbnail_loc>
<video:description>A counterfeit coin that might be heavy or light, a balance that only reports which side falls, and a hundred dollars a weighing. Counting rules out four; only a construction gets you five.</video:description>
<video:player_loc>https://www.youtube-nocookie.com/embed/s2Gwg6nLdlY</video:player_loc>
<video:duration>764</video:duration>
<video:publication_date>2026-08-01T01:00:00Z</video:publication_date>
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<loc>https://lambdia.com/a/riemann-vs-lebesgue</loc>
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<video:title>Every Upper Sum Says One, Every Lower Sum Says Zero, and the Gap Is the Measure of the</video:title>
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<video:description>On the unit interval the indicator of the rationals has upper sum 1 and lower sum 0 for every partition ever written, so the two never meet and Riemann returns nothing at all. Give the k-th rational an interval of width ε/2^k and the whole countable set sits inside a total length of ε, which puts its measure at 0 and its Lebesgue integral at 0. Lebesgue's criterion turns that into the general law — a bounded function on a compact interval is Riemann integrable exactly when its discontinuities have measure zero — which is why Thomae's function, discontinuous on the same dense set, is integrable and this one is not. The trade is not free: sin x over x on the half line has an improper Riemann value of π/2 and no Lebesgue integral at all.</video:description>
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<video:publication_date>2026-08-01T12:00:00Z</video:publication_date>
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